document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565693>Question 565693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul has 35 coins consisting of dimes and nickels. The value of his coins is $3.30 How many of each type does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365920 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'd' be the number of dimes and 'n' the number of nickels. Then 10d+5n=330 and d+n=35. Substituting the second equation into the first we get 10(35-n)+5n=330. So Paul has n=4 nickles and 31 dimes. </SPAN>\n" );
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