document.write( "Question 565645: find the smallest of three consecutive positive integers such that the product of two smaller integers is 68 more than twice the largest integer \n" ); document.write( "

Algebra.Com's Answer #365916 by ad_alta(240) $\"\"$ $\"About$

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Let 'n' be the smallest integer. Then n(n+1)=68+2(n+2). We get n=9. The positive integers are 9, 10, 11. \n" ); document.write( "

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