document.write( "Question 565566: This really confuses me since it showed be put in the formula I=prt. If this was explained that would help! Thanks.\r
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document.write( "Madison invested $50,000 for two years. A part of this investment had 10% annual interest and the rest was invested at 15% annual interest. The interest from the investment at 10% was $350 more than the interest from the investment at 15%. How much did she invest at 10%? How much did she invest at 15%? \n" );
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Algebra.Com's Answer #365894 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Madison invested $50,000 for two years. A part of this investment had 10% annual interest and the rest was invested at 15% annual interest. The interest from the investment at 10% was $350 more than the interest from the investment at 15%. How much did she invest at 10%? How much did she invest at 15%? \n" ); document.write( "**\r \n" ); document.write( "\n" ); document.write( "I=prt, p=initial investment, r=annual rate of interest, and I=amt after t years \n" ); document.write( ".. \n" ); document.write( "let x=$ amt invested at 10% \n" ); document.write( "50000-x=$ amt invested at 15% \n" ); document.write( ".. \n" ); document.write( "At 10% \n" ); document.write( "I=(10%*2)x=.2x \n" ); document.write( "At 15% \n" ); document.write( "I=(15%*2)(50000-x)=(15000-.3x) \n" ); document.write( "Since the 10% investment made $350 more than the 15% investment, \n" ); document.write( ".2x-(15000-.3x)=350 \n" ); document.write( ".2x-15000+.3x=350 \n" ); document.write( ".5x=15350 \n" ); document.write( "x=30700 \n" ); document.write( "50000-x=19300 \n" ); document.write( "ans: \n" ); document.write( "amt invested at 10%=$30,700 \n" ); document.write( "amt invested at 15%=$19,300 \n" ); document.write( " |