document.write( "Question 565566: This really confuses me since it showed be put in the formula I=prt. If this was explained that would help! Thanks.\r
\n" ); document.write( "\n" ); document.write( "Madison invested $50,000 for two years. A part of this investment had 10% annual interest and the rest was invested at 15% annual interest. The interest from the investment at 10% was $350 more than the interest from the investment at 15%. How much did she invest at 10%? How much did she invest at 15%?
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Algebra.Com's Answer #365894 by lwsshak3(11628)\"\" \"About 
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Madison invested $50,000 for two years. A part of this investment had 10% annual interest and the rest was invested at 15% annual interest. The interest from the investment at 10% was $350 more than the interest from the investment at 15%. How much did she invest at 10%? How much did she invest at 15%?
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\n" ); document.write( "\n" ); document.write( "I=prt, p=initial investment, r=annual rate of interest, and I=amt after t years
\n" ); document.write( "..
\n" ); document.write( "let x=$ amt invested at 10%
\n" ); document.write( "50000-x=$ amt invested at 15%
\n" ); document.write( "..
\n" ); document.write( "At 10%
\n" ); document.write( "I=(10%*2)x=.2x
\n" ); document.write( "At 15%
\n" ); document.write( "I=(15%*2)(50000-x)=(15000-.3x)
\n" ); document.write( "Since the 10% investment made $350 more than the 15% investment,
\n" ); document.write( ".2x-(15000-.3x)=350
\n" ); document.write( ".2x-15000+.3x=350
\n" ); document.write( ".5x=15350
\n" ); document.write( "x=30700
\n" ); document.write( "50000-x=19300
\n" ); document.write( "ans:
\n" ); document.write( "amt invested at 10%=$30,700
\n" ); document.write( "amt invested at 15%=$19,300
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