document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565542>Question 565542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36 meters. If the width is 3 times the length, find the demensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365864 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'w' be the width and 'l' the length. Then 2w+2l=36 and w=3l. Substituting, 2(3l)+2l=36. We must have l=4.5 and w=13.5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );