document.write( "Question 565547: 10. The Purdue special train is driving to a city that is hosting a Purdue sporting event. The Special leaves campus at 10:00AM and is travelling at a constant rate of 40 miles per hour. A car full of fans leaves campus at 11:30 AM and travels the same route at a constant rate of 70 miles per hour. At what time will the car catch up with the Special? \n" ); document.write( "
Algebra.Com's Answer #365862 by stanbon(75887)\"\" \"About 
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The Special leaves campus at 10:00AM and is travelling at a constant rate of 40 miles per hour. A car full of fans leaves campus at 11:30 AM and travels the same route at a constant rate of 70 miles per hour. At what time will the car catch up with the Special?
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\n" ); document.write( "Special DATA:
\n" ); document.write( "rate = 40 mph ; time = x hrs ; distance = 40x miles
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\n" ); document.write( "Fan DATA:
\n" ); document.write( "rate = 70 mph ; time = (x-(3/2)) hrs ; distance = 70(x-(3/2)) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "40x = 70(x-(3/2))
\n" ); document.write( "40x = 70x - 105
\n" ); document.write( "30x = 105
\n" ); document.write( "x = 3.5 hrs
\n" ); document.write( "---
\n" ); document.write( "Catch-up time would be 10AM + 3 1/2 hrs = 1:30 PM
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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