document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52996>Question 52996</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> given that (3x-a)(x-2)(x-7)= 3x^3-32^2+18x-70 determine the value of a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36586 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given that (3x-a)(x-2)(x-7)= 3x^3-32^2+18x-70 determine the value of a<BR>\n" );
document.write( "PUT X=1<BR>\n" );
document.write( "(3*1-A)(1-2)(1-7)=3*1^3-32*1^2+18*1-70=-81<BR>\n" );
document.write( "(3-A)6=-81<BR>\n" );
document.write( "3-A=-81/6=-27/2<BR>\n" );
document.write( "6-2A=-27<BR>\n" );
document.write( "2A=33<BR>\n" );
document.write( "A=16.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );