document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54259>Question 54259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/7x + 5/9y = 27<BR>\n" );
document.write( "1/9x + 2/7y = 7 <BR>\n" );
document.write( "Solve each system by the addition method <BR>\n" );
document.write( " can someone who understands this help thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36585 by </B><A HREF=/tutors/aboutme.mpl?userid=jenrobrody><B>jenrobrody(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jenrobrody><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/7x + 5/9y = 27<BR>\n" );
document.write( "1/9x + 2/7y = 7 \r<BR>\n" );
document.write( "\n" );
document.write( "It may be easier to cancel out fractions by multiplying both sides by LCD=63\r<BR>\n" );
document.write( "\n" );
document.write( "63(3/7x + 5/9y) = 63(27)     AND        63(1/9x +2/7y) = 63(7)<BR>\n" );
document.write( "   189/7x + 315/9y = 1701;          ;      63/9x + 126/7y = 441<BR>\n" );
document.write( "    27x  +  35y = 1701;             ;       7x  + 18y   = 441\r<BR>\n" );
document.write( "\n" );
document.write( "so we have an equivalent problem:     27x + 35y = 1701<BR>\n" );
document.write( "                                       7x + 18y = 441<BR>\n" );
document.write( "to cancel out x's, we need 189x and -189x<BR>\n" );
document.write( "multiply first equation by 7:     189x + 245y = 11907<BR>\n" );
document.write( "multiply second equation by -27:  -189x - 486y = -11907<BR>\n" );
document.write( "               add:                  0x -241y = 0<BR>\n" );
document.write( "                                        -241y = 0<BR>\n" );
document.write( "                                            y = 0<BR>\n" );
document.write( "substitute into either equation to solve for x:<BR>\n" );
document.write( "3/7x + 5/9(0) = 27<BR>\n" );
document.write( "3/7x = 27<BR>\n" );
document.write( "(7/3)(3/7x) = (7/3)(27)<BR>\n" );
document.write( "         x = 63<BR>\n" );
document.write( "(x,y)=(63,0)\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "3/7(63) + 5/9(0) = 9*7 + 0 = 27<BR>\n" );
document.write( "1/9(63) + 2/7(0) = 63/9 + 0 = 7  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );