document.write( "Question 54319: Investing. John invests twice as much money at 6% as he does 5%. If his investments earn a total of $680 in 1 year, how much does he have invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #36584 by stanbon(75887)\"\" \"About 
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John invests twice as much money at 6% as he does 5%. If his investments earn a total of $680 in 1 year, how much does he have invested at each rate?
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\n" ); document.write( "Let amount invested at 5% be \"x\".
\n" ); document.write( "Interest on that money is 0.05x dollars
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\n" ); document.write( "Amount invested at 6% is \"2x\".
\n" ); document.write( "Interest on that money is 0.06(2x)=0.12x
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\n" ); document.write( "EQUATION:
\n" ); document.write( "0.05x + 0.12x = 680
\n" ); document.write( "0.17x=680
\n" ); document.write( "x=$4000 (Amount invested at 5%)
\n" ); document.write( "2x=$8000 (Amount invested at 6%)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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