document.write( "Question 54319: Investing. John invests twice as much money at 6% as he does 5%. If his investments earn a total of $680 in 1 year, how much does he have invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #36584 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! John invests twice as much money at 6% as he does 5%. If his investments earn a total of $680 in 1 year, how much does he have invested at each rate? \n" ); document.write( "--------- \n" ); document.write( "Let amount invested at 5% be \"x\". \n" ); document.write( "Interest on that money is 0.05x dollars \n" ); document.write( "---------- \n" ); document.write( "Amount invested at 6% is \"2x\". \n" ); document.write( "Interest on that money is 0.06(2x)=0.12x \n" ); document.write( "---------- \n" ); document.write( "EQUATION: \n" ); document.write( "0.05x + 0.12x = 680 \n" ); document.write( "0.17x=680 \n" ); document.write( "x=$4000 (Amount invested at 5%) \n" ); document.write( "2x=$8000 (Amount invested at 6%) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |