document.write( "Question 565512: James is 19 times as old as Bill. Frank is 30 Years younger than James. In 6 Years James' age will be twice the sum of bill and Frank's ages then. How old is James?\r
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Algebra.Com's Answer #365836 by Leaf W.(135)\"\" \"About 
You can put this solution on YOUR website!
Bill: x
\n" ); document.write( "James: 19x
\n" ); document.write( "Frank: 19x - 30
\n" ); document.write( "Bill's age in six years: x + 6
\n" ); document.write( "James's age in six years: 19x + 6
\n" ); document.write( "Frank's age in six years: 19x - 24
\n" ); document.write( "Since James's age in six years will be twice the sum of Bill's and Frank's ages then, your equation is 19x + 6 = 2(x + 6 + 19x - 24)
\n" ); document.write( "Add like terms: 19x + 6 = 2(20x - 18)
\n" ); document.write( "Distribute the 2: 19x + 6 = 40x - 36
\n" ); document.write( "Add 36 to both sides: 19x + 42 = 40x
\n" ); document.write( "Subtract 19x from both sides: 42 = 21x
\n" ); document.write( "Divide both sides by 21: 2 = x
\n" ); document.write( "Therefore, Bill's is two years old. Plug this value into the expression for James's age, 19x.
\n" ); document.write( "19x = 19(2) = 38
\n" ); document.write( "***THEREFORE, JAMES IS 38 YEARS OLD.***
\n" ); document.write( "Hope I helped! =)
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