document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565488>Question 565488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word problems give me a very hard time. Figuring out how to set up the problem is my biggest problem. Can u please help me.\r<BR>\n" );
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document.write( "The height of a box is 8inches. The length is three inches more thane the width. Find the width if the volume is 144.\r<BR>\n" );
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document.write( "Inches-8<BR>\n" );
document.write( "Width-3(x)<BR>\n" );
document.write( "Volume-144<BR>\n" );
document.write( " So would it be : 3(x) + 8= 144? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365812 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V = L * W * H ___ 144 = L * W * 8 ___ 18 = L * W\r<BR>\n" );
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document.write( "\"The length is three inches more thane the width\" ___ L = W + 3\r<BR>\n" );
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document.write( "substituting ___ 18 = (W + 3)(W) ___ 18 = W^2 + 3W ___ 0 = W^2 + 3W - 18\r<BR>\n" );
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document.write( "factoring ___ 0 = (W + 6)(W - 3) </SPAN>\n" );
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