document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565474>Question 565474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve the linear system by using the substitution method and showing details please. Thank you\r<BR>\n" );
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document.write( "3x+4y=-3<BR>\n" );
document.write( "2x+y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365802 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solving the 2nd eqn for y ___ y = 8 - 2x\r<BR>\n" );
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document.write( "substituting the value for y into the 1st eqn ___ 3x + 4(8 - 2x) = -3 ___ 3x + 32 - 8x = -3 ___ -5x = -35\r<BR>\n" );
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document.write( "solve for x, and then substitute back to find y </SPAN>\n" );
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