document.write( "Question 565334: the length of a rectangle is 4 cm greater than its width. If the length and the width were increased by 3 cm, the area of the rectangle would be in creased by 93 cm. What are the dimensions fo the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #365765 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! he length of a rectangle is 4 cm greater than its width. If the length and the width were increased by 3 cm, the area of the rectangle would be in creased by 93 cm. What are the dimensions fo the original rectangle? \n" ); document.write( "** \n" ); document.write( "let w=width of original rectangle \n" ); document.write( "w+4=length of original rectangle \n" ); document.write( ".. \n" ); document.write( "w+3=width of enlarged rectangle \n" ); document.write( "w+4+3=w+7=length of enlarged rectangle \n" ); document.write( ".. \n" ); document.write( "area=length*width \n" ); document.write( "(w+3)(w+7)-w(w+4)=93 \n" ); document.write( "w^2+10w+21-w^2-4w=93 \n" ); document.write( "6w=72 \n" ); document.write( "w=12 \n" ); document.write( "w+4=16 \n" ); document.write( "ans: \n" ); document.write( "width of original rectangle=12 cm \n" ); document.write( "length of original rectangle=16 cm \n" ); document.write( ".. \n" ); document.write( " |