document.write( "Question 565334: the length of a rectangle is 4 cm greater than its width. If the length and the width were increased by 3 cm, the area of the rectangle would be in creased by 93 cm. What are the dimensions fo the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #365765 by lwsshak3(11628)\"\" \"About 
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he length of a rectangle is 4 cm greater than its width. If the length and the width were increased by 3 cm, the area of the rectangle would be in creased by 93 cm. What are the dimensions fo the original rectangle?
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\n" ); document.write( "let w=width of original rectangle
\n" ); document.write( "w+4=length of original rectangle
\n" ); document.write( "..
\n" ); document.write( "w+3=width of enlarged rectangle
\n" ); document.write( "w+4+3=w+7=length of enlarged rectangle
\n" ); document.write( "..
\n" ); document.write( "area=length*width
\n" ); document.write( "(w+3)(w+7)-w(w+4)=93
\n" ); document.write( "w^2+10w+21-w^2-4w=93
\n" ); document.write( "6w=72
\n" ); document.write( "w=12
\n" ); document.write( "w+4=16
\n" ); document.write( "ans:
\n" ); document.write( "width of original rectangle=12 cm
\n" ); document.write( "length of original rectangle=16 cm
\n" ); document.write( "..
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