document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565318>Question 565318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you tell me how to do this problem. I have not had Algebra before so I need to be sure I'm on the right track.\r<BR>\n" );
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document.write( "2x + 6 =30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365763 by </B><A HREF=/tutors/aboutme.mpl?userid=Tias_411><B>Tias_411(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tias_411><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Tias_411><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you want to get your (2x) by itself so you subtract 6 from both sides of your equation. 2x + 6 =30<BR>\n" );
document.write( "                  - 6  -6        <BR>\n" );
document.write( "               ___________<BR>\n" );
document.write( "               2x     =24<BR>\n" );
document.write( "*your 6's will cancel out. <BR>\n" );
document.write( "now you want x by itself so you divide both sides by 2.<BR>\n" );
document.write( "               2x =24<BR>\n" );
document.write( "               /2  /2<BR>\n" );
document.write( "                x= 12<BR>\n" );
document.write( "*your 2's canceled to get you x by itself. </SPAN>\n" );
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