document.write( "Question 54310: If Joe & Jane have a total of 40 coins consisting of nickels & dimes totaling $3.00. How many nickels & dimes do they have.\r
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Algebra.Com's Answer #36575 by funmath(2933) $\"\"$ $\"About$

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Let the number of dimes you have =x
\n" ); document.write( "Then if we subtract the dimes from the rest of the 40 coins we will have the nickels: 40-x
\n" ); document.write( "The amount of money that we have in coins is the worth of the coin times the number of coins, it's easier to solve these in terms of cents instead of dollars.
\n" ); document.write( "We have this amount of money:
\n" ); document.write( "In dimes:10x
\n" ); document.write( "In nickels:5(40-x)
\n" ); document.write( "All together: 300 (cents)
\n" ); document.write( "Your problem to solve:
\n" ); document.write( "10x+5(40-x)=300
\n" ); document.write( "10x+200-5x=300
\n" ); document.write( "(10-5)x+200=300
\n" ); document.write( "5x+200=300
\n" ); document.write( "5x+200-200=300-200
\n" ); document.write( "5x=100
\n" ); document.write( "5x/5=100/5
\n" ); document.write( "x=20
\n" ); document.write( ":
\n" ); document.write( "Dimes: $\"highlight%28x=20%29\"$
\n" ); document.write( "Nickels:40-x= $\"highlight%2840-20=20%29\"$
\n" ); document.write( ":
\n" ); document.write( "Check to see if this is true, does 20 dimes + 20 nickels=$3.00
\n" ); document.write( ".10(20)+.05(20)=$3.00
\n" ); document.write( "$2.00+$1.00=$3.00
\n" ); document.write( "Looks like we're right!!!
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "

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