document.write( "Question 565266: Prove that nCr is less than or equal to n+1Cr+1\r
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document.write( ". Hint: Make use of the fact that if A ≤ B then A/B ≤1. \n" );
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Algebra.Com's Answer #365741 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Pascal's triangle easily proves it, as\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since nC(r+1) is nonnegative, nCr <= (n+1)C(r+1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or, we can show that\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both numerator and denominator by 1/(denominator)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by n!r!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is true because we're choosing r objects out of n, so it is reasonable to assume r <= n. \n" ); document.write( " |