document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565267>Question 565267</A>: <I><SPAN STYLE=\"word-break: break-all;\">     So and so rode her bike from her house to the beach and walked back home. The total travel time was 2 hours. If she averaged 9 mph on the bike and 4 mph walking, how far is it from her house to the beach? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365726 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to know her name to solve the problem! Just kidding ;)<BR>\n" );
document.write( "Remember that the distance to the beach is the same as the distance home. Therefore 9t_1=4t_2 (for the two different times). Moreover, t_1+t_2=2. Substituting, 9t_1=4(2-t_1). So t_1=8/13. The distance is then (8/13)(9), or about 5.54 miles. Why did she leave her bike at the beach? Now that's a good question. </SPAN>\n" );
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