document.write( "Question 564822: Sarah takes 40 minutes to walk to her office and only 12 min if she rides her bike. Her speed when walking is 7 miles per hour less than her speed when riding her bike. (assume she takes the same path to her office). What is the distance to her office. \n" ); document.write( "
Algebra.Com's Answer #365709 by ankor@dixie-net.com(22740)\"\" \"About 
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Sarah takes 40 minutes to walk to her office and only 12 min if she rides her bike.
\n" ); document.write( " Her speed when walking is 7 miles per hour less than her speed when riding her bike. (assume she takes the same path to her office).
\n" ); document.write( " What is the distance to her office.
\n" ); document.write( ":
\n" ); document.write( "Let s = his walking speed
\n" ); document.write( "then
\n" ); document.write( "(s+7) = his biking speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "We need the time in hrs
\n" ); document.write( ":
\n" ); document.write( "\"40%2F60\"s = \"12%2F60\"(s+7)
\n" ); document.write( "Reduce the fractions
\n" ); document.write( "\"2%2F3\"s = \"1%2F5\"(s+7)
\n" ); document.write( "Multiply by 15 to clear the denominators
\n" ); document.write( "5(2s) = 3(s+7)
\n" ); document.write( "10s = 3s + 21
\n" ); document.write( "10s - 3s = 21
\n" ); document.write( "7s = 21
\n" ); document.write( "s = 21/7
\n" ); document.write( "s = 3 mph is his walking speed
\n" ); document.write( ":
\n" ); document.write( "Find the distance
\n" ); document.write( "\"2%2F3\"(3) = 2 miles
\n" ); document.write( "Check the distance
\n" ); document.write( "\"1%2F5\"(3+7) = 2 miles also \n" ); document.write( "
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