document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565183>Question 565183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 40 percent of the length. The perimeter of the rectangle is 42. Find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365693 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'l' be the length and 'w' the width. Then w=0.4l and 2l+2w=42. Substituting, 2l+2(0.4l)=42. Therefore l=15 and w=6. </SPAN>\n" );
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