document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565171>Question 565171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 6 AM a snowplow, traveling at a constant speed, begins clearing a highway leading out of town. A 8 AM an automobile traveling the highway at a speed at 30 mi/hr and reaches the snowplow 30 minutes late. Find the seed of the snowplow. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365676 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Snowplow speed be x\r<BR>\n" );
document.write( "\n" );
document.write( "in 2 hours before the car starts it has traveled 2x miles\r<BR>\n" );
document.write( "\n" );
document.write( "Catch up distance = 2x<BR>\n" );
document.write( "catchup time = 1/2 hour<BR>\n" );
document.write( "catchup rate = 30-x  ( since they are travelling in same directions\r<BR>\n" );
document.write( "\n" );
document.write( "2x/(30-x)=1/2\r<BR>\n" );
document.write( "\n" );
document.write( "cross multiply<BR>\n" );
document.write( "4x=30-x<BR>\n" );
document.write( "4x-x=30<BR>\n" );
document.write( "2x= 30<BR>\n" );
document.write( "/2 <BR>\n" );
document.write( "x=15 mph---- speed of snowplow </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );