document.write( "Question 565170: larry is 8 years older than his sister. in 3 years, he will be twice as old as she is now. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #365675 by mananth(16946)\"\" \"About 
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Sister's age =x
\n" ); document.write( "Larry's age = x+8\r
\n" ); document.write( "\n" ); document.write( "After 3 years Larry's age = x+8+3=x+11\r
\n" ); document.write( "\n" ); document.write( "x+11=2x
\n" ); document.write( "2x-x=11
\n" ); document.write( "x=11, sister's age now\r
\n" ); document.write( "\n" ); document.write( "Larry = 11+8 =19 years
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