document.write( "Question 565084: A rectangle has a width of 4X – 6, the length is triple this distance. IF the perimeter is 112. Find the value of X, the length, width and area of this rectangle.\r
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Algebra.Com's Answer #365646 by nyc_function(2741)\"\" \"About 
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P = 2L + 2W\r
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\n" ); document.write( "\n" ); document.write( "112 = 2(12x - 18) + 2(4x - 6)\r
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\n" ); document.write( "\n" ); document.write( "After doing the math, I got x = 5.\r
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\n" ); document.write( "\n" ); document.write( "width = 4(5) - 6 or 14\r
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\n" ); document.write( "\n" ); document.write( "length = 12(5) - 18 or 42\r
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\n" ); document.write( "\n" ); document.write( "Area = length times width\r
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\n" ); document.write( "\n" ); document.write( "Area = 14 times 42 or 588\r
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