document.write( "Question 565030: Hello my questions is with this equation: ((x->y)^(y->z))->(x->z)
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document.write( "I'm suppose to prove that it is a tautology through a truth table. I was just wondering when you throw that third letter in there (z) how does the truth table start. Is it that there are now 6 rows instead of a normal 4 with two variables. like x would start with three T's and three F's? Thanks in advance
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Algebra.Com's Answer #365570 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Hello my questions is with this equation: ((x->y)^(y->z))->(x->z) \n" ); document.write( "I'm suppose to prove that it is a tautology through a truth table. I was just wondering when you throw that third letter in there (z) how does the truth table start. Is it that there are now 6 rows instead of a normal 4 with two variables. like x would start with three T's and three F's? Thanks in advance \n" ); document.write( "------- \n" ); document.write( "Use the following pattern: \n" ); document.write( "x.....y....z \n" ); document.write( "t.....t....t \n" ); document.write( "t.....t....f \n" ); document.write( "t.....f....t \n" ); document.write( "t.....f....f \n" ); document.write( "f.....t....t \n" ); document.write( "f.....t....f \n" ); document.write( "f.....f....t \n" ); document.write( "f.....f....f \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |