document.write( "Question 565023: Suppose $6,500 is divided into two bank accounts. One account pays 10% simple interest per year and the other pays 4.6%. After two years there is a total of $1000 in interest between the two accounts. How much was invested into the bank account that pays 4.6% simple interest (rounded to the nearest cent)? \n" ); document.write( "
Algebra.Com's Answer #365569 by stanbon(75887)\"\" \"About 
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Suppose $6,500 is divided into two bank accounts. One account pays 10% simple interest per year and the other pays 4.6%. After two years there is a total of $1000 in interest between the two accounts. How much was invested into the bank account that pays 4.6% simple interest (rounded to the nearest cent)?
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\n" ); document.write( "Equation:
\n" ); document.write( "interest + interest = interest
\n" ); document.write( "0.10x + 0.046(6500-x) = 500
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\n" ); document.write( "Multiply thru by 1000 to get:
\n" ); document.write( "100x + 46*6500 - 46x = 500000
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\n" ); document.write( "54x = $201,000
\n" ); document.write( "x = $3722.22 (amt. invested at 10%
\n" ); document.write( "6500 - x = $2777.78 (amt. invested at 4.6%\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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