document.write( "Question 54233: This is for anyone familiar with the FOIL Method. I have to find the product of:\r
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document.write( "(2y - 5)(y - 2) using the FOIL Method.\r
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document.write( "What I have so far is:\r
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document.write( "2y^2 - 2y -5y + 10
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document.write( "10 + -2y + -5y + 2y^2
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document.write( "-2y + -5y = -7y
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document.write( "10 + -7y + 2y^2\r
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document.write( "Is this in any way correct? \n" );
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Algebra.Com's Answer #36555 by Cintchr(481)![]() ![]() ![]() You can put this solution on YOUR website! You miscalculated ... \n" ); document.write( "(2y - 5)(y - 2) \n" ); document.write( "F: 2y * y = 2y^2 \n" ); document.write( "O: 2y * -2 = -4y \n" ); document.write( "I: -5 * y = -5y \n" ); document.write( "L: -5 * -2 = -10 \n" ); document.write( "Add the O and I \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |