document.write( "Question 564939: how do i solve k(k-3)=28 \n" ); document.write( "

Algebra.Com's Answer #365533 by issacodegard(60) $\"\"$ $\"About$

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Distribute the k:
\n" ); document.write( "k(k-3)=28
\n" ); document.write( "k*k-k*3=28
\n" ); document.write( "k^2-3k=28
\n" ); document.write( "Subtract 28:
\n" ); document.write( "k^2-3k-28=0
\n" ); document.write( "Factor:
\n" ); document.write( "(k-7)(k+4)=0
\n" ); document.write( "Since the product of two expressions is zero for some k, one of them must be zero. This implies:
\n" ); document.write( "k-7=0 OR k+4=0
\n" ); document.write( "This implies:
\n" ); document.write( "k=7 OR k=-4 \n" ); document.write( "

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