document.write( "Question 564909: Hey! Im currently in e2020 and im a visual learner NOT a person who learns just by hearing, but im in need of someone to help me on this math problem:
\n" ); document.write( "finding the vertex of y=x^2+3x-4 \n" ); document.write( "
Algebra.Com's Answer #365522 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Hey! Im currently in e2020 and im a visual learner NOT a person who learns just by hearing, but im in need of someone to help me on this math problem:
\n" ); document.write( "finding the vertex of y=x^2+3x-4
\n" ); document.write( "**
\n" ); document.write( "Since this is a 2nd degree equation you should know that its graph is a parabola.
\n" ); document.write( "The standard form of this equation: y=A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve.
\n" ); document.write( "..
\n" ); document.write( "To rewrite equation in standard form, complete the square:
\n" ); document.write( "y=(x^2+3x+9/4)-4-9/4
\n" ); document.write( "y=(x+3/2)^2-45/4
\n" ); document.write( "This is an equation of a parabola with vertex at (-3/2,-45/4).
\n" ); document.write( "Since the lead coefficient>0, parabola opens upwards
\n" ); document.write( "see graph below as a visual check:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-12%2C+12%2C+-12%2C+12%2C+%28x%2B3%2F2%29%5E2-45%2F4%29+\" \n" ); document.write( "
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