document.write( "Question 564891: 
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document.write( "Solving equations: find the real number solutions of the equation.\r\n" );
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document.write( "     g³ + 3g² - g - 3 = 0\r\n" );
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Algebra.Com's Answer #365521 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "     g³ + 3g² - g - 3 = 0\r\n" );
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document.write( "Factor the first two terms g³ + 3g² by taking out the common factor \r\n" );
document.write( "g², getting g²(g + 3).\r\n" );
document.write( "Factor the last two terms -g - 3 by taking out the common factor \r\n" );
document.write( "-1, getting -1(g + 3).\r\n" );
document.write( "So the equation is now:\r\n" );
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document.write( " g²(g + 3) - 1(g + 3) = 0\r\n" );
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document.write( "Now factor out the common factor (g + 3)\r\n" );
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document.write( "      (g + 3)(g² - 1) = 0\r\n" );
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document.write( "Now the expression in the second parentheses g² - 1 can be factored as the\r\n" );
document.write( "difference of two squares as (g - 1)(g + 1) and the equation is now:\r\n" );
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document.write( "(g + 3)(g - 1)(g + 1) = 0\r\n" );
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document.write( "Us the principle of zero factors and set each factor = 0, and solve:\r\n" );
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document.write( "   g + 3 = 0;   g - 1 = 0;   g + 1 = 0\r\n" );
document.write( "       g = -3;      g = 1;       g = -1\r\n" );
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document.write( "The solutions are these three: -3, 1, and -1.\r\n" );
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document.write( "Edwin
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