document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564716>Question 564716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3ft less than twice the width of the rectangle. Tha perimeter is 174ft what is width and length  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365491 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'l' be the length and 'w' the width. We know l+3=2w and 2w+2l=174. Substitute l=2w-3 into the second equation and get 2w+2(2w-3)=174. We get w=30 and l=57. </SPAN>\n" );
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