document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564749>Question 564749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/10(e-2) is less than or equal to 3/5e - 1/4\r<BR>\n" );
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document.write( "I'm fairly sure I'm supposed to find the least common denominater (?) for the fractions, which is 20, and would change the fractions to 6/20, 12/20, and 5/20, but if that's right, do I also multiply (e-2) by 20? I'm so confused. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365466 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/10(e-2) is less than or equal to 3/5e - 1/4<BR>\n" );
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document.write( "First, I will write the equation I believe is the given problem:<BR>\n" );
document.write( "(3/10)(e-2)&#8804;(3/5)e-1/4<BR>\n" );
document.write( "3(e-2)/10&#8804;3e/5-1/4<BR>\n" );
document.write( "LCD:20 (like you said)<BR>\n" );
document.write( "6(e-2)&#8804;12e-5 (yes, you should multiply 6*(e-2))<BR>\n" );
document.write( "6e-12)&#8804;12e-5<BR>\n" );
document.write( "-6e&#8804;7<BR>\n" );
document.write( "Divide by -6 and reverse inequality sign<BR>\n" );
document.write( "e&#8805;-7/6<BR>\n" );
document.write( "solution in interval notation<BR>\n" );
document.write( "[-7/6,&#8734;) </SPAN>\n" );
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