document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564715>Question 564715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3ft less than twice tha width of the rectangle. Tha perimeter is 174ft what is width and length  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365457 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter =	174							<BR>\n" );
document.write( "Width 	=		x	ft										<BR>\n" );
document.write( "Length  =(2x-3)							<BR>\n" );
document.write( "Perimeter =2((2x-3)+x)<BR>\n" );
document.write( "Perimeter =	2(2x-3	+x)			<BR>\n" );
document.write( "Perimeter =4x-6+2x				<BR>\n" );
document.write( "174	=6x-6								<BR>\n" );
document.write( "							<BR>\n" );
document.write( "174	+	6	=	6x									<BR>\n" );
document.write( "180	=	6x											<BR>\n" );
document.write( "x=	30.00		ft	Width 										<BR>\n" );
document.write( "Length  	=		57	ft										<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );