document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564719>Question 564719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The John Hancock Center in Chicago has a rectangular base.  The length of the base measures 65 feet less than twice the width.  The perimeter of this base is 860 feet.  What are the dimensions of the base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365450 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter =	860												<BR>\n" );
document.write( "Width 	=x	ft										<BR>\n" );
document.write( "Length  2x-65							<BR>\n" );
document.write( "Perimeter =	2((2x-65)+x)<BR>\n" );
document.write( "Perimeter =	2(	2x-65+x)			<BR>\n" );
document.write( "Perimeter =	4x-130+2x				<BR>\n" );
document.write( "860	=6x-130								<BR>\n" );
document.write( "860	+	130	=	6	x									<BR>\n" );
document.write( "990	=	6	x											<BR>\n" );
document.write( "x=	165		ft	Width 										<BR>\n" );
document.write( "Length  	=		265	ft										 </SPAN>\n" );
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