document.write( "Question 54301This question is from textbook
\n" ); document.write( ": I am a nursing student and I am required to take college algebra. I took it on line and I am really struggling. Please help, I have to pass this class to move on to my next nursing class in January.
\n" ); document.write( "Use the following function definitions f(x)=-x^+2x g(x)=!3-2x!(absolute value)
\n" ); document.write( "h(x)=sqrt 5-x p(x)=2/x to evaluate the following: (g+h)(2)=________________
\n" ); document.write( "(h/p)(-3)=________________.
\n" ); document.write( "For part 1 I have g(2)+h(2)= 2!3-2x!+2(sqrt 5-2) =2!3-2x!+10-4
\n" ); document.write( " = 2!3-2x!+6
\n" ); document.write( "The instructor did not give an example w/ absolute value or square roots and his questions do not come from the book. We had to have cds burned at the beginning of the semester. I am not book smart and I'm just not getting this. Thanks so much for your help.
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Algebra.Com's Answer #36545 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Use the following function definitions
\n" ); document.write( "f(x)=-x^+2x
\n" ); document.write( "g(x)=!3-2x!(absolute value)
\n" ); document.write( "h(x)=sqrt 5-x
\n" ); document.write( "p(x)=2/x
\n" ); document.write( "-------------
\n" ); document.write( "to evaluate the following:
\n" ); document.write( "(g+h)(2)= g(2) + h(2)
\n" ); document.write( "=|3-2*2| + sqrt5 -2
\n" ); document.write( "=1 + sqrt5 -2
\n" ); document.write( "=-1+sqrt5
\n" ); document.write( "---------------
\n" ); document.write( "(h/p)(-3)
\n" ); document.write( "= h(-3)/p(-3)
\n" ); document.write( "=[sqrt5--3]/[2/(-3)]
\n" ); document.write( "=[sqrt5 + 3]/[-2/3]
\n" ); document.write( "=(-3/2)(sqrt5 +3)
\n" ); document.write( "--------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "_______________.
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