document.write( "Question 564213: what are all ordered pairs of numbers (x, y) which satisfy x^2 – xy + y^2 = 7 and x- xy + y = -1 ?\r
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Algebra.Com's Answer #365449 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Add 3xy to both sides of the 1st equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second equation is equivalent to\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is a quadratic in x+y, and the solutions are x+y = 5 and x+y = -2. If x+y = 5, substituting into the second equation we obtain\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And if x+y = -2, substituting into the second equation yields\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore we have two cases: x+y = 5 & xy = 6, and x+y = -2 & xy = -1. The first case yields {3,2}; the second case we can let x = -2-y, in which\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By the quadratic formula, |