document.write( "Question 564653: A chemist has 500L of a 15% acid solution. How much pure acid should be added to make a 20% acid solution?
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Algebra.Com's Answer #365447 by Maths68(1474)\"\" \"About 
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Solution A
\n" ); document.write( "Amount = 500 liters
\n" ); document.write( "Concentration =15% =0.15\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =100% = 1\r
\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =500+x
\n" ); document.write( "Concentration =20%=0.2\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant\r
\n" ); document.write( "\n" ); document.write( "(500)(0.15)+(x)(1)=(500+x)(.02)
\n" ); document.write( "75+1x=100+0.2x
\n" ); document.write( "1x-0.2x=100-75
\n" ); document.write( "0.8x=25
\n" ); document.write( "0.8x/0.8=25/8
\n" ); document.write( "x=20\r
\n" ); document.write( "\n" ); document.write( "He should add 20 liters of pure acide to make a 20% acid solution?
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