document.write( "Question 564656: How many gallons of 60% antifreeze solution must be mixed with 70 gallons of 15% antifreeze to get a mixture of 50% antifreeze. \n" ); document.write( "
Algebra.Com's Answer #365432 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ------------------------percent ---------------- quantity \n" ); document.write( "Antifreeze type I 15----------------70 gallons \n" ); document.write( "Antifreeze type II 60----------------x gallons \n" ); document.write( "Mixture 50----------------70+x gallons \n" ); document.write( " \n" ); document.write( "15*70+60x=50(70+x) \n" ); document.write( "1050+60x=3500+50x \n" ); document.write( "60x-50x=3500-1050 \n" ); document.write( "10x=2450 \n" ); document.write( "/ 10 \n" ); document.write( "x= 245 gallons of Antifreeze type II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |