document.write( "Question 564656: How many gallons of 60% antifreeze solution must be mixed with 70 gallons of 15% antifreeze to get a mixture of 50% antifreeze. \n" ); document.write( "
Algebra.Com's Answer #365432 by mananth(16946)\"\" \"About 
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------------------------percent ---------------- quantity
\n" ); document.write( "Antifreeze type I 15----------------70 gallons
\n" ); document.write( "Antifreeze type II 60----------------x gallons
\n" ); document.write( "Mixture 50----------------70+x gallons
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\n" ); document.write( "15*70+60x=50(70+x)
\n" ); document.write( "1050+60x=3500+50x
\n" ); document.write( "60x-50x=3500-1050
\n" ); document.write( "10x=2450
\n" ); document.write( "/ 10
\n" ); document.write( "x= 245 gallons of Antifreeze type II
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\n" ); document.write( "m.ananth@hotmail.ca
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