document.write( "Question 564462: Please solve the following system of linear equations with substitution.
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document.write( "3x-2=y
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document.write( "y-2x=-5 \n" );
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Algebra.Com's Answer #365386 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 3x - 2 = y \n" ); document.write( "y - 2x =-5 \n" ); document.write( "From the 1st equation we know that y = 3x - 2, therefore we can replace y with (3x-2) in the 2nd equation \n" ); document.write( "(3x-2) - 2x = -5 \n" ); document.write( "3x - 2x = -5 + 2 \n" ); document.write( "x = -3 \n" ); document.write( ": \n" ); document.write( "Find y \n" ); document.write( "y = 3x - 2 \n" ); document.write( "we know x=-3 \n" ); document.write( "y = 3(-3) - 2 \n" ); document.write( "y = -9 - 2 \n" ); document.write( "y = -11 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solutions of x=-3, y=-11 in the 2nd equation \n" ); document.write( "y - 2x = -5 \n" ); document.write( "replace x with -3, y with -11 \n" ); document.write( "-11 - 2(-3) = -5 \n" ); document.write( "minus a minus is a plus so we have \n" ); document.write( "-11 + 6 = -5; which is true so our solution check out \n" ); document.write( " |