document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564350>Question 564350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth $3 a pound that she wishes to mix with 50 pounds of coffee worth $9 a pound to get a mixture worth $8 a pound. How many pounds of the $3 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365341 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The average cost needs to come to $8 a pound. Thus, if 'x' is the number of pounds of $3/lb coffee the merchant needs to add, we have (3*x+50*9)/(x+50)=8. Thus, x=10. I'm sure the merchant will sell it for $9 a pound anyway... </SPAN>\n" );
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