document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564250>Question 564250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the radius of a circle when the center is at (3,5) and it passes through the origin? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365301 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the radius you need a point along the circle and the center. The center is (3,5) the point along the circle is the origin (0,0)\r<BR>\n" );
document.write( "\n" );
document.write( "We can use distance formula to solve from here, and the zeros will make this easy<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28%283-0%29%5E2%2B%285-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28%283-0%29%5E2%2B%285-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%289%2B25%29 ALIGN=MIDDLE  ALT=\"d=sqrt%289%2B25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%2834%29 ALIGN=MIDDLE  ALT=\"d=sqrt%2834%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );