document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564144>Question 564144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pond is being drained by a pump. After 3 hours, the pond is half empty. A second pump is put into operation, and together the two pumps finish emptying the pond in half an hour. How long would it take the second pump to drain the pond if it had to do the same job alone. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365253 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pump A -3 hours <BR>\n" );
document.write( "so it does 1/3 of the job in 1 hour\r<BR>\n" );
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document.write( "Pump A + B = 1/2 hour <BR>\n" );
document.write( "so they do 1/(1/2) of the job in 1 hour=2\r<BR>\n" );
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document.write( "difference = 2-1/3= 5/6 of the job in 1 hour\r<BR>\n" );
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document.write( "so for 1 job Pump B will take 6/5 hours<BR>\n" );
document.write( "1  1/5 hours </SPAN>\n" );
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