document.write( "Question 54271: find the vertex, focus, directrix of the parabola by x^2 -4x -6y -16 = 0 \n" ); document.write( "
Algebra.Com's Answer #36525 by stanbon(75887)\"\" \"About 
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find the vertex, focus, directrix of the parabola by x^2 -4x -6y -16 = 0
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\n" ); document.write( "Rewrite as:
\n" ); document.write( "x^2-4x+? = 6y+16+?
\n" ); document.write( "Complete the square:
\n" ); document.write( "x^2-4x+4=6y+16+4
\n" ); document.write( "(x-2)^2 = 6(y+(10/3))
\n" ); document.write( "This follows the form (x-h)^2=4p(y-k)
\n" ); document.write( "h=2; k=-10/3; p=3/2
\n" ); document.write( "Vertex at (2,10/3); focus=(2,(10/3)+(3/2))=(2,29/6);
\n" ); document.write( "directrix: y = (10/3)-(3/2)=11/6
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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