document.write( "Question 564032: solve the equation...(q+2/3)+(q-4/4)=2 I thought you would start by finding the LCM, which would be 12, but it is confusing me when it comes to the variables being added in. \n" ); document.write( "
Algebra.Com's Answer #365227 by ankor@dixie-net.com(22740)\"\" \"About 
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solve the equation...(q+2/3)+(q-4/4)=2
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\n" ); document.write( "\"%28q%2B2%29%2F3\"+\"%28q-4%29%2F4\" = 2
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\n" ); document.write( "Multiply by the Lowest common denominator,
\n" ); document.write( "12*\"%28q%2B2%29%2F3\" + 12*\"%28q-4%29%2F4\" = 12(2)
\n" ); document.write( "Cancel the denominators and you have
\n" ); document.write( "4(q+2) + 3(q-4) = 24
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\n" ); document.write( "4q + 8 + 3q - 12 = 24
\n" ); document.write( "7q - 4 = 24
\n" ); document.write( "7q = 24 + 4
\n" ); document.write( "7q = 28
\n" ); document.write( "q = 28/7
\n" ); document.write( "q = 4
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\n" ); document.write( "See if that works in the original problem
\n" ); document.write( "\"%284%2B2%29%2F3\"+\"%284-4%29%2F4\" = 2
\n" ); document.write( "\"6%2F3\"+\"0%2F4\" = 2
\n" ); document.write( "2 + 0 = 2\r
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