document.write( "Question 564032: solve the equation...(q+2/3)+(q-4/4)=2 I thought you would start by finding the LCM, which would be 12, but it is confusing me when it comes to the variables being added in. \n" ); document.write( "
Algebra.Com's Answer #365227 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! solve the equation...(q+2/3)+(q-4/4)=2 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by the Lowest common denominator, \n" ); document.write( "12* \n" ); document.write( "Cancel the denominators and you have \n" ); document.write( "4(q+2) + 3(q-4) = 24 \n" ); document.write( ": \n" ); document.write( "4q + 8 + 3q - 12 = 24 \n" ); document.write( "7q - 4 = 24 \n" ); document.write( "7q = 24 + 4 \n" ); document.write( "7q = 28 \n" ); document.write( "q = 28/7 \n" ); document.write( "q = 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that works in the original problem \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2 + 0 = 2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |