document.write( "Question 563971: A freight train traveling at an average rate of 30 kilometers per hour is followed 2 hours later from the same station by a passenger train traveling at an average rate of 50 kilometers per hour. How many hours after the passenger train leaves will it pass the freight train? \n" ); document.write( "

Algebra.Com's Answer #365224 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A freight train traveling at an average rate of 30 kilometers per hour is followed 2 hours later from the same station by a passenger train traveling at an average rate of 50 kilometers per hour.
\n" ); document.write( " How many hours after the passenger train leaves will it pass the freight train.
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\n" ); document.write( "Let t = travel time of the pass train
\n" ); document.write( "then
\n" ); document.write( "(t+2) = travel time of the freight
\n" ); document.write( ":
\n" ); document.write( "When the pass train catches the freight, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "pass dist = freight dist
\n" ); document.write( "50t = 30(t+2)
\n" ); document.write( "50t = 30t + 60
\n" ); document.write( "50t - 30t = 60
\n" ); document.write( "20t = 60
\n" ); document.write( "t = 60/20
\n" ); document.write( " t = 3 hrs for the pass train to catch freight
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "see if that checks out both should travel the same dist
\n" ); document.write( "50(3) = 30(3+2)
\n" ); document.write( "150 = 150 \n" ); document.write( "

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