document.write( "Question 563840: Suppose that Annette invests $7000 at 7%. How much must she invest at 11% so that the total yearly interest from the two investments exceeds $974? \n" ); document.write( "
Algebra.Com's Answer #365200 by mananth(16946)\"\" \"About 
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let her invest $x @ 11%\r
\n" ); document.write( "\n" ); document.write( "7000 @ 7%\r
\n" ); document.write( "\n" ); document.write( "Interest =974\r
\n" ); document.write( "\n" ); document.write( "0.11x+0.07*7000=974\r
\n" ); document.write( "\n" ); document.write( "multiply by 100
\n" ); document.write( "11x+49000=974*100\r
\n" ); document.write( "\n" ); document.write( "11x= 97400-49000\r
\n" ); document.write( "\n" ); document.write( "11x=48400\r
\n" ); document.write( "\n" ); document.write( "x=4400 @ 11%\r
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