document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=564063>Question 564063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and simplify...(q+2)/3+(q-4)/4=2 I thought I would start out by finding the LCM but I am confusing myself more than anything. Can you please help me solve this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve and simplify...(q+2)/3+(q-4)/4=2 I thought I would start out by finding the LCM but I am confusing myself more than anything. Can you please help me solve this.<BR>\n" );
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document.write( "LCM of 3 and 4 is 12<BR>\n" );
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document.write( "Multiply thru by 12 to get:<BR>\n" );
document.write( "4(q+2) + 3(q-4) = 2*12<BR>\n" );
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document.write( "4q+8 + 3q-12 = 24<BR>\n" );
document.write( "7q -4 = 24<BR>\n" );
document.write( "7q = 28<BR>\n" );
document.write( "q = 4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================ </SPAN>\n" );
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