document.write( "Question 54266This question is from textbook Algebra for College Students
\n" ); document.write( ": To solve for this equation, \"6x%2B5%3C11\" or \"3x-1%3E8\" I would have to do the same to both sides correct? if I (-5) to the 11 side I must do the same to the 8 side right? From there I would solve for x normally and that gives me the 2 answers? I think I have the logic down, just need to make sure my steps are correct.
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Algebra.Com's Answer #36519 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
To solve for this equation,\r\n" );
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document.write( "    6x+5 < 11 OR 3x-1 > 8\r\n" );
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document.write( "I would have to do the same to both sides correct? \r\n" );
document.write( "if I (-5) to the 11 side I must do the same to the \r\n" );
document.write( "8 side right? From there I would solve for x normally \r\n" );
document.write( "and that gives me the 2 answers? I think I have the\r\n" );
document.write( "logic down, just need to make sure my steps are\r\n" );
document.write( "correct. \r\n" );
document.write( "Thank you\r\n" );
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document.write( "First of all that is a two-part inequality, not an\r\n" );
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document.write( "Solve each part separately\r\n" );
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document.write( "6x + 5 < 11  OR  3x - 1 > 8\r\n" );
document.write( "    -5   -5          +1  +1\r\n" );
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document.write( "6x     < 6   OR  3x     > 9\r\n" );
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document.write( "Divide both sides of first by 6\r\n" );
document.write( "Divide both sides of second by 3\r\n" );
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document.write( "     x < 1   OR       x > 3 \r\n" );
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document.write( "Graph: Since x can be either\r\n" );
document.write( "left of 1 or else right of 3, we\r\n" );
document.write( "shade everwhere x can be: \r\n" );
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document.write( "<==============o-----o==========>\r\n" );
document.write( "  -3 -2 -1  0  1  2  3  4  5  6\r\n" );
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document.write( "Interval notation:   (-oo, 1) U (3, oo)\r\n" );
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document.write( "Edwin
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