document.write( "Question 54266This question is from textbook Algebra for College Students
\n" ); document.write( ": To solve for this equation, \"6x%2B5%3C11\" or \"3x-1%3E8\" I would have to do the same to both sides correct? if I (-5) to the 11 side I must do the same to the 8 side right? From there I would solve for x normally and that gives me the 2 answers? I think I have the logic down, just need to make sure my steps are correct.
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Algebra.Com's Answer #36516 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
\"6x+%2B+5+%3C+11\"
\n" ); document.write( "\"6x+%3C+6\"
\n" ); document.write( "\"x+%3C+1\"
\n" ); document.write( "or
\n" ); document.write( "\"3x+-+1+%3E+8\"
\n" ); document.write( "\"3x+%3E+9\"
\n" ); document.write( "\"x+%3E+3\"
\n" ); document.write( "<===) 1 --- 3 (===>
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