document.write( "Question 563953: I need hep solving:
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document.write( "(1/3)^x+1 = 9^x\r
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document.write( "I made the bases the same:
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document.write( "9^-2(x+1) = 9^x\r
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document.write( "Then I set the exponents as an equation:
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document.write( "2x + 2 = x
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document.write( "2 = -x
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document.write( "X = -2\r
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document.write( "When I checked the back of my book for the answer I saw it was -1/3 and I don't how to get it. \n" );
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Algebra.Com's Answer #365157 by TutorDelphia(193) You can put this solution on YOUR website! (1/3)^x+1 = 9^x \n" ); document.write( "you made a mistake making the bases the same: \n" ); document.write( "9^-2=1/81 so that doesn't work \n" ); document.write( "you want \n" ); document.write( "9^-(1/2)=1/3 \n" ); document.write( "So you get: \n" ); document.write( "9^-(1/2)(x+1) = 9^x \n" ); document.write( "-(1/2)(x+1) simplifies to -1/2x-1/2 since you have to distribute the negative 1/2\r \n" ); document.write( "\n" ); document.write( "-(1/2)x-1/2=x \n" ); document.write( "Multiply both sides by 2 to clear the fraction \n" ); document.write( "-x-1=2x \n" ); document.write( "add x to both sides \n" ); document.write( "-1=3x \n" ); document.write( "divide both sides by 3 \n" ); document.write( "x=-1/3\r \n" ); document.write( "\n" ); document.write( "Difficult problem! \n" ); document.write( " |