document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54267>Question 54267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the center and radius of the circle given by x(squared)- 4x + y(squared) -6y + 12 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36515 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 - 4x + y^2 - 6y = -12<BR>\n" );
document.write( "(x - 2)^2 + (y - 3)^2 = -12 + 4 + 9 = 1<BR>\n" );
document.write( "(x - 2)^2 + (y - 3)^2 = 1<BR>\n" );
document.write( "radius = 1<BR>\n" );
document.write( "center = (2,3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );