document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=563933>Question 563933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve 2x^3 + 2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365147 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem looks tricky but can actually be solved in just a few steps<BR>\n" );
document.write( "2x^3 + 2=0<BR>\n" );
document.write( "subtract 2 from both sides<BR>\n" );
document.write( "2x^3=-2<BR>\n" );
document.write( "divide both sides by 2<BR>\n" );
document.write( "x^3=-1\r<BR>\n" );
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document.write( "Take the cube root of both sides, which will give you<BR>\n" );
document.write( "x=-1\r<BR>\n" );
document.write( "\n" );
document.write( "since -1*-1*-1=-1 </SPAN>\n" );
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