document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=563781>Question 563781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity of 65 percent acid solution must be mixed with a 25 percent solution to produce 576 mL of a 50 percent solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365141 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 65% solution needed\r<BR>\n" );
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document.write( "Now we know that the pure acid that exists before the solutions are mixed together has to equal the amount of pure acid after the solutions are mixed together, soooooo:\r<BR>\n" );
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document.write( "0.65x+0.25(576-x)=0.50*576 simplify<BR>\n" );
document.write( "0.65x+144-0.25x=288 subtract 144 from each side<BR>\n" );
document.write( "0.40x=144<BR>\n" );
document.write( "x=360 ml----amount of 65% solution needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.65*360+0.25*(576-360)=0.50*575<BR>\n" );
document.write( "234+54=288<BR>\n" );
document.write( "288=288\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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